30x^2+21x+3=0

Solution for 30x^2+21x+3=0 equation:

30x^2+21x+3=0

a = 30; b = 21; c = +3;
Δ = b2-4ac
Δ = 212-4·30·3
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-9}{2*30}=\frac{-30}{60}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+9}{2*30}=\frac{-12}{60}
=-1/5
$